495001100
For any positive real numbers x,y, and z, the following equation holds:
(x⋆y)⋆z=(x⋆y)z+1x⋆y=xy+1xz+1xy+1x=xy+xz+1x=x(y+z)+1x=x⋆(y+z).
Using this repeatedly, we have:
((⋯((((100⋆99)⋆98)⋆97)⋆96)⋆⋯⋆3)⋆2)⋆1=((⋯((((100⋆(99+98))⋆97)⋆96)⋆⋯⋆3)⋆2)⋆1=((⋯((100⋆(99+98+97))⋆96)⋆⋯⋆3)⋆2)⋆1=⋯=100⋆(99+98+97+⋯+3+2+1)=100⋆299⋅100.
Therefore, the answer is 100⋆4950=495001100.