Let ABC be a triangle with AB=13, BC=14, CA=15. Company XYZ wants to locate their base at the point P in the plane minimizing the total distance to their workers, who are located at vertices A, B, and C. There are 1, 5, and 4 workers at A, B, and C, respectively. Find the minimum possible total distance Company XYZ's workers have to travel to get to P.
Solution
Solution:
We want to minimize 1⋅PA+5⋅PB+4⋅PC. By the triangle inequality, (PA+PB)+4(PB+PC)≥AB+4BC=13+56=69, with equality precisely when P=[AB]∩[BC]=B.
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Source: MathNet,
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