Let LOVER be a convex pentagon such that LOVE is a rectangle. Given that OV=20 and LO=VE=RE=RL=23, compute the radius of the circle passing through R, O, and V.
Solution
Solution:
Let X be the point such that RXOL is a rhombus. Note that line RX defines a line of symmetry on the pentagon LOVER. Then by symmetry RXVE is also a rhombus, so RX=OX=VX=23. This makes X the center of the circle, and the radius is 23.
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