Juku drew a regular hexagon and chose three triangles with different areas whose vertices were among the vertices of the hexagon. Prove that the sum of the areas of the triangles is equal to the area of the hexagon.
, 2010
Solution
Any triangle whose vertices are among the vertices of a regular hexagon is one of the following:
* a triangle whose vertices are three consecutive vertices of the hexagon;
* a triangle whose two vertices are adjacent vertices of the hexagon and the third one is adjacent to none of the first two;
* a triangle where any two vertices are not adjacent vertices of the hexagon.
Since the areas of the chosen triangles are different, the triangles must be equal to the triangles , , . The hexagon can be divided into four parts (Fig. 9): the triangle surrounded by three triangles . The area of the triangle (marked by a dotted line in Fig. 9) is twice the area of the triangle because they have the same base but the height of is twice the height of .