Maths Olympiad Prep

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Geometry Difficulty 5.1 AIME, harder Prove it United States

Problem:

Circle BB has radius 676 \sqrt{7}. Circle AA, centered at point CC, has radius 7\sqrt{7} and is contained in BB. Let LL be the locus of centers CC such that there exists a point DD on the boundary of BB with the following property: if the tangents from DD to circle AA intersect circle BB again at XX and YY, then XYX Y is also tangent to AA. Find the area contained by the boundary of LL.

Solution

Solution:

The conditions imply that there exists a triangle such that BB is the circumcircle and AA is the incircle for the position of AA. The distance between the circumcenter and incenter is given by (R2r)R\sqrt{(R-2 r) R}, where R,rR, r are the circumradius and inradius, respectively. Thus the locus of CC is a circle concentric to BB with radius 2422 \sqrt{42}. The conclusion follows.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.