Number theoryDifficulty 4.6AIMEProve itSaudi Arabia
Prove that there are no positive integers x, y, z such that (3x+4y)(4x+5y)=7z
Solution
From the condition, we can see that both numbers 3x+4y and 4x+5y are powers of 7, so such must be also their division. However 1<3x+4y4x+5y<2 and can't be power of 7.
Want a route through all this instead of an archive? The track
puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.
Source: MathNet,
licensed CC-BY-4.0.
Statement and solution reproduced as published; topic and difficulty added by this site.