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Geometry Difficulty 4.6 AIME Prove it Ireland

Let AA, BB, CC be three points on a circle of centre OO. The perpendicular line from OO to BCBC intersects line ACAC at PP, and the perpendicular line from OO to ACAC intersects line BCBC at QQ. Let LL be the midpoint of OCOC and KK the midpoint of PQPQ.
Prove that KLKL is perpendicular on ABAB.

Solution

The quadrilateral CNOM is cyclic because CNO=90\angle CNO = 90^\circ and CMO=90\angle CMO = 90^\circ, and OCOC is a diameter and LL the centre of its circumcircle.
Figure 1
The quadrilateral MNPQ is cyclic as well since PNQ=PMQ=90\angle PNQ = \angle PMQ = 90^\circ, and PQPQ is a diameter and KK the centre of its circumcircle. The line MN is the radical axis of these two circles and so is perpendicular to the line KL which connects the centres of the circles. Because M and N are midpoints of sides of ABC\triangle ABC, MNABMN \parallel AB, hence ABKLAB \perp KL.

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