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Algebra Difficulty 4.9 AIME Prove it Ukraine

Solve the equation for arbitrary distinct reals aa, bb, cc:
x3axa3+a3bab3+b3xbx3=(xa)(xb)(xc)(ab). x^3 a - x a^3 + a^3 b - a b^3 + b^3 x - b x^3 = (x-a)(x-b)(x-c)(a-b).

Solution

Obviously the equation can be solved by trivial transformations and reduction to a quadratic one. We suggest a different approach. Denote the left-hand and right-hand sides by f(x)f(x) and g(x)g(x) respectively. It's easy to verify that f(a)=g(a)=0f(a) = g(a) = 0 and f(b)=g(b)=0f(b) = g(b) = 0. But this implies that distinct numbers aa, bb are roots of this equation. By comparing the coefficients at x3x^3 for both sides, we conclude that our equation is quadratic. Hence, x=ax=a and x=bx=b are its only roots.

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