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IMO Team Selection Contest I

Geometry Difficulty 7.8 National Olympiad, round 2 Prove it Estonia

Let ABCABC be a triangle with AB=AC≠BCAB = AC \ne BC and let II be its incenter. The line BIBI meets ACAC at DD, and the line through DD perpendicular to ACAC meets AIAI at EE. Prove that the reflection of II in ACAC lies on the circumcircle of triangle BDEBDE.

Solution

Solution. See IMO 2016 shortlist, problem G4.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.