Maths Olympiad Prep

Library / /1 of 5

Geometry Difficulty 7.8 National olympiad, round 2 Prove it Estonia

Let ABCABC be a triangle with AB=ACBCAB = AC \ne BC and let II be its incenter. The line BIBI meets ACAC at DD, and the line through DD perpendicular to ACAC meets AIAI at EE. Prove that the reflection of II in ACAC lies on the circumcircle of triangle BDEBDE.

Solution

Solution. See IMO 2016 shortlist, problem G4.

Want a route through all this instead of an archive? The track puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.

Source: MathNet, licensed CC-BY-4.0. Statement and solution reproduced as published; topic and difficulty added by this site.