Problem:
Find all real positive solutions (if any) to
, 2003
Solutions — 3
Solution 1
Solution:
Let . The first equation above is equivalent to . If , then with equality only if . But if , then the second equation is not satisfied. So in any solution to the system of equations, at least one of the variables is less than 1. Without loss of generality, suppose that . Then
Therefore the system has no real positive solutions.
Solution 2
Solution:
We will show that the system has no real positive solution. Assume otherwise.
The second equation can be written . Since this quadratic in has a real solution by hypothesis, its discriminant is nonnegative. Hence
Dividing through by yields
Hence and so , being positive. A similar argument yields . But the first equation can be written as
contradicting . Hence, a real positive solution cannot exist.
Solution 3
Solution:
Applying the arithmetic-geometric mean inequality and the Power Mean Inequalities to we have
Letting and , this inequality can be written
Now implies , so . Also implies ,
so . But then and which is inconsistent with . Therefore the system cannot have a real positive solution.