Maths Olympiad Prep

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Combinatorics Difficulty 6.6 National olympiad Prove it

For a positive integer nn, there are two countries AA and BB with nn airports each and n22n+2n^2-2n+ 2 airlines operating between the two countries. Each airline operates at least one flight. Exactly one flight by one of the airlines operates between each airport in AA and each airport in BB, and that flight operates in both directions. Also, there are no flights between two airports in the same country. For two different airports PP and QQ, denote by "*(P,Q)(P, Q)-travel route*" the list of airports T0,T1,,TsT_0, T_1, \ldots, T_s satisfying the following conditions.
[list]
[*] T0=P, Ts=QT_0=P,\ T_s=Q
[*] T0,T1,,TsT_0, T_1, \ldots, T_s are all distinct.
[*] There exists an airline that operates between the airports TiT_i and Ti+1T_{i+1} for all i=0,1,,s1i = 0, 1, \ldots, s-1.
[/list]
Prove that there exist two airports P,QP, Q such that there is no or exactly one *(P,Q)(P, Q)-travel route*.

Consider a complete bipartite graph G(A,B)G(A, B) with A=B=n\vert A \vert = \vert B \vert = n. Suppose there are n22n+2n^2-2n+2 colors and each edge is colored by one of these colors. Define (P,Q)path(P, Q)-path a path from PP to QQ such that all of the edges in the path are colored the same. Prove that there exist two vertices PP and QQ such that there is no or only one (P,Q)path(P, Q)-path.

Solution

1. Restate the problem in graph-theoretical terms:
- We have a bipartite graph G(A,B) G(A, B) where A=B=n |A| = |B| = n .
- There are n22n+2 n^2 - 2n + 2 colors, and each edge in G G is colored with one of these colors.
- Each color is used on at least one edge.
- We need to prove that there exist two vertices P P and Q Q such that there is no or exactly one (P,Q)(P, Q)-path, where a (P,Q)(P, Q)-path is a path from P P to Q Q such that all edges in the path are the same color and all vertices in the path are distinct.

2. Initial observations:
- The total number of edges in a complete bipartite graph Kn,n K_{n,n} is n2 n^2 .
- Since we have n22n+2 n^2 - 2n + 2 colors, there are 2n2 2n - 2 edges that are not used.

3. Consider the structure of the graph:
- Each vertex in A A is connected to each vertex in B B by a unique edge.
- Since there are n22n+2 n^2 - 2n + 2 edges, we can think of removing 2n2 2n - 2 edges from the complete bipartite graph Kn,n K_{n,n} .

4. **Analyze the implications of removing 2n2 2n - 2 edges:**
- Removing 2n2 2n - 2 edges from Kn,n K_{n,n} means that some vertices in A A and B B will have fewer connections.
- Specifically, each vertex in A A and B B will have at least n2 n - 2 connections remaining.

5. Consider the coloring of the edges:
- Each color is used on at least one edge.
- Since there are n22n+2 n^2 - 2n + 2 colors, each color corresponds to a unique edge or a set of edges.

6. **Prove the existence of P P and Q Q with no or exactly one (P,Q)(P, Q)-path:**
- Suppose for contradiction that for every pair of vertices P P and Q Q , there are at least two (P,Q)(P, Q)-paths.
- This would imply that there are multiple paths of the same color connecting P P and Q Q , which contradicts the fact that we have removed 2n2 2n - 2 edges and each color is used on a unique set of edges.

7. Conclusion:
- Therefore, there must exist at least one pair of vertices P P and Q Q such that there is no or exactly one (P,Q)(P, Q)-path.

\blacksquare

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.