To solve: $\dfrac {x^{2}-x-6}{x-1} > 0 \Leftrightarrow \dfrac {(x-3)(x+2)}{(x-1)} > 0 \Leftrightarrow (x-3)(x+2)(x-1) > 0$
By using the method of interval testing, we find that $-2 3$,
Therefore, the correct choice is: $\boxed{C}$.
To solve $\dfrac {f(x)}{g(x)} > 0$, it can be transformed into $f(x) \cdot g(x) > 0$, and then solved using the method of interval testing.
This question mainly examines the methods of solving rational inequalities and polynomial inequalities, and is considered a basic question on inequalities.