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Algebra Difficulty 2.9 Junior Find the answer

Which of the following operations is correct?

Pick one

Solution

To solve this problem, let's examine each option step by step:

Option A: a2+a4a^{2}+a^{4}

- This option suggests adding two powers of aa. However, without a common exponent, these terms cannot be combined through addition. Therefore, a2+a4a6a^{2}+a^{4} \neq a^{6}.

Option B: a2a3a^{2}\cdot a^{3}

- When multiplying terms with the same base, we add their exponents according to the rule aman=am+na^{m} \cdot a^{n} = a^{m+n}. Thus, a2a3=a2+3=a5a^{2}\cdot a^{3} = a^{2+3} = a^{5}, not a6a^{6}.

Option C: (a2)3(-a^{2})^{3}

- Raising a term to a power involves multiplying the exponent inside the parentheses by the outside exponent. For (a2)3(-a^{2})^{3}, we get (1)3a23=a6(-1)^{3} \cdot a^{2\cdot3} = -a^{6}, which is not equal to a6a^{6} due to the negative sign.

Option D: a8÷a2a^{8}\div a^{2}

- When dividing terms with the same base, we subtract the exponent of the denominator from the exponent of the numerator according to the rule am÷an=amna^{m} \div a^{n} = a^{m-n}. Therefore, a8÷a2=a82=a6a^{8}\div a^{2} = a^{8-2} = a^{6}.

Given the examination above, the correct operation is found in Option D, where a8÷a2=a6a^{8}\div a^{2}=a^{6}.

Thus, the correct answer is D\boxed{D}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.