32. (i) For any positive integer k, it must be true that 3k∣23k−1+1,3k+1∤2k−1+1. (ii) Let k,s be positive integers. Prove: 3k∣2s+1 if and only if 2∤s,3k−1∣s.
Solution
32. (i) Use induction; (ii) Sufficiency follows from (i). Note that when 2∣s, 3∤2s+1, set s=3t. f,(f,6)=1, use (i) to prove necessity.
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