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Algebra Difficulty 2.4 Junior Find the answer

Given the complex number z=3i1+iz= \frac{3-i}{1+i} (where ii is the imaginary unit), find the real part of zz.

A number or a short expression. Spacing and $ signs are ignored.

Solution

Analysis

This question tests the division operation of complex numbers in algebraic form and the basic concept of complex numbers. It is a fundamental question.

Solution

Since z=3i1+i=(3i)(1i)(1+i)(1i)=24i2=12iz= \frac{3-i}{1+i}= \frac{(3-i)(1-i)}{(1+i)(1-i)}= \frac{2-4i}{2}=1-2i,
the real part of zz is 11.
Therefore, the answer is 1\boxed{1}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.