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Algebra Difficulty 2.4 Junior Find the answer

Given the function f(x)={3x,(x>0)x13,(x0)f(x)= \begin{cases} 3^{x}, & (x > 0) \\ -x^{ \frac {1}{3}}, & (x\leqslant 0)\end{cases}, find the value of f(log34)f(\log _{3}4).

A number or a short expression. Spacing and $ signs are ignored.

Solution

Since log34>0\log _{3}4 > 0, we use the first part of the piecewise function:
f(x)=3xf(x) = 3^{x}
Thus,
f(log34)=3log34f(\log _{3}4) = 3^{\log _{3}4}
Using the property of logarithms that says alogan=na^{\log_a{n}} = n, we get:
f(log34)=3log34=4f(\log _{3}4) = 3^{\log _{3}4} = 4
Therefore, the answer is 4\boxed{4}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.