Maths Olympiad Prep

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Algebra Difficulty 6.4 National olympiad Prove it

31. Given a,b,c>0a, b, c>0, and a+b+c=abca+b+c=abc, prove: 11+a2+11+b2+11+c232(1998\frac{1}{\sqrt{1+a^{2}}}+\frac{1}{\sqrt{1+b^{2}}}+\frac{1}{\sqrt{1+c^{2}}} \leqslant \frac{3}{2} \cdot\left(1998^{-}\right. Korean Mathematical Olympiad problem)

Solution

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