Example 1 As shown in Figure 2.3.1, from a point A outside circle O, a tangent is drawn, touching the circle at B. Through the midpoint M of AB, a secant is drawn intersecting the circle at C and D. Lines AC and AD intersect the circle again at E and F. Prove: AB∥EF.
Solution
From MA2=MB2=MC⋅MD, we can prove △AMC∼△DMA, from which we have ∠CAM=∠CDA. Also, ∠CDA=∠CEF, thus ∠CAM=∠CEF (alternate interior angles), AB//EF is proven.
Want a route through all this instead of an archive? The track
puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.
Source: NuminaMath-1.5,
licensed Apache-2.0.
Statement and solution reproduced as published; topic and difficulty added by this site.