Maths Olympiad Prep

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Geometry Difficulty 5.4 AIME, harder Prove it

Example 1 As shown in Figure 2.3.1, from a point AA outside circle OO, a tangent is drawn, touching the circle at BB. Through the midpoint MM of ABAB, a secant is drawn intersecting the circle at CC and DD. Lines ACAC and ADAD intersect the circle again at EE and FF. Prove: ABEFAB \parallel EF.

Solution

From MA2=MB2=MCMDM A^{2}=M B^{2}=M C \cdot M D, we can prove AMCDMA\triangle A M C \sim \triangle D M A, from which we have CAM=CDA\angle C A M=\angle C D A. Also, CDA=CEF\angle C D A=\angle C E F, thus CAM=CEF\angle C A M=\angle C E F (alternate interior angles), AB//EFA B / / E F is proven.

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