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Algebra Difficulty 4.7 AIME Find the answer
1. Given that a, b, c are three consecutive odd numbers in increasing order. Then the value of a2−2b2+c2 is
A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.
Solution
−1.8.
Since a=b−2,c=b+2, then,
a2−2b2+c2=b2−4b+4−2b2+b2+4b+4=8.
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