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Geometry Difficulty 4.7 AIME Find the answer

6. Given a regular tetrahedron ABCDABCD with edge length 2, the sum of the areas of all sections obtained by planes equidistant from its four vertices is:

Pick one

Solution

6.D.

There are two types of such cross-sections:
(1) One side of the cross-section has one point, and the other side has three points, such as B1C1D1\triangle B_{1} C_{1} D_{1} in Figure 4(a), where B1,C1,D1B_{1}, C_{1}, D_{1} are the midpoints of edges AB,AC,ADAB, AC, AD respectively. There are four such cross-sections, each with an area of 34\frac{\sqrt{3}}{4};
(2) Both sides of the cross-section have two points each, such as the quadrilateral MNPQMNPQ in Figure 4(b), where M,N,P,QM, N, P, Q are the midpoints of edges AB,BC,CD,DAAB, BC, CD, DA respectively. There are three such cross-sections, all of which are squares, each with an area of 1.
In summary, the total area of all cross-sections is 3+33+\sqrt{3}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.