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Geometry Difficulty 2.6 Junior Find the answer

Let mm, nn, and ll be three different lines, and α\alpha, β\beta, and γ\gamma be three different planes. Then, the correct proposition is

Pick one

Solution

For option A, if αγ\alpha \perp \gamma and βγ\beta \perp \gamma, then it could be that αβ\alpha \parallel \beta or α\alpha intersects β\beta. Therefore, option A is incorrect.

For option B, if mβm \parallel \beta and lml \perp m, then it could be that lβl \perp \beta, lβl \parallel \beta, or ll is contained in β\beta. Therefore, option B is incorrect.

For option C, if mαm \parallel \alpha and nαn \parallel \alpha, then it could be that mnm \parallel n, mm intersects nn, or mm and nn are skew lines. Therefore, option C is incorrect.

For option D, if mαm \perp \alpha and nαn \perp \alpha, then mnm \parallel n. Therefore, option D is correct.

Hence, the correct choice is D\boxed{\text{D}}.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic and difficulty added by this site.