The answer to this problem is the number of intersections between the graph of $f(x) = \sin x$ and $f(x) = \frac{1}{100}x.$ We can do the right side of the coordinate plane first. Each cycle of the sine wave, consisting of 2π, will have 2 intersections (From the positive part of the sine wave) The line $f(x) = \frac{1}{100}x$ will consist of 16 cycles plus a little bit extra for $x$ from 1 to 100. However, the extra is not complete enough to have any intersection at all. Thus, the number of intersections is $2 \cdot 16 = 32.$ Because of symmetry, we can multiply by two to account for the left side, and subtract one because of the origin. So the answer is $32 \cdot 2 - 1 = \textbf{(C)}\ 63.$
https://www.desmos.com/calculator/z6edqwu1kx - Graph

~Eric X