### Part (a)
1. **Define the function d(X) for X∈S(T)**:
- Choose an arbitrary point T0∈T.
- Define d(X) as the distance from X to T0.
2. **Boundedness of S(T)**:
- Notice that S(T) is bounded by a circle of radius 2012+2013=4025 centered at T0.
- This is because any point Q∈S(T) satisfies ∣QP∣≤2013 for some P∈T, and ∣P1P2∣≤2012 for any P1,P2∈T.
3. **Closedness of S(T)**:
- S(T) is closed. For any convergent sequence of points in S(T) whose limit has a distance strictly more than 2013 from all points in T, we can find some point far enough along in the sequence that it too has a distance strictly more than 2013 from all points in T, contradicting its membership in S(T).
4. **Compactness of S(T)**:
- Since S(T) is both bounded and closed, it is a compact set.
5. **Existence of a maximum for d**:
- The continuous function d on S(T) attains a maximum at some point S0.
6. **Constructing a line in L**:
- The line through S0 perpendicular to T0S0 will intersect S(T) at exactly one point, S0.
- Therefore, L is nonempty.
### Part (b)
1. Definition of a bad line:
- A line ℓ0 passing through O is bad if there does not exist a line ℓ∈L parallel to (or coinciding with) ℓ0.
2. **Sweeping lines parallel to ℓ0**:
- If ℓ0 is bad, then sweeping lines parallel to ℓ0 across the plane means each one that intersects S(T) intersects it multiple times.
- This implies it intersects the convex envelope of S(T) multiple times.
3. Convex envelope and line segments:
- The convex envelope of S(T) must have a finite number of line segments of positive length.
- Suppose, for the sake of contradiction, there were an uncountably infinite number of (positive length) line segments.
4. Lemma: Sum of an uncountably infinite set of strictly positive numbers is infinite:
- Argue by contradiction and assume it were finite and equal to some M.
- For each n∈N, the set {x∈S∣x>1/n} is finite (in particular, has size at most Mn).
- The union of these sets is S, but the countable union of finite sets is countable, contradicting the uncountability of S.
5. Contradiction:
- It follows that the convex envelope of S(T) must have infinite perimeter, but finite area (from the boundedness of S(T)).
- Consider the set S′(T) of points which are within some ϵ>0 of some point in S(T); clearly this figure has bounded area as well.
- By convexity, [S′(T)]−[S(T)]≥Pϵ where P is the perimeter of the convex envelope of S(T).
- This contradicts the fact that S(T) has infinite perimeter.
6. Countability of bad lines:
- Therefore, the set of bad lines is countable.
- We can assign a line ℓ(i) to each positive integer i so that for every bad line ℓ0 passing through O, there exists a positive integer n with ℓ(n)=ℓ0.
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