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HMMT February

Algebra Difficulty 4.8 AIME Find the answer

Find the exact value of 1+11+21+11+21+…1+\frac{1}{1+\frac{2}{1+\frac{1}{1+\frac{2}{1+\ldots}}}}.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Let xx be what we are trying to find. x−1=11+21+11+21+…⇒1x−1−1=21+11+21+⋯⇒21x−1−1=x⇒x2−2=0x-1=\frac{1}{1+\frac{2}{1+\frac{1}{1+\frac{2}{1+\ldots}}}} \Rightarrow \frac{1}{x-1}-1=\frac{2}{1+\frac{1}{1+\frac{2}{1+\cdots}}} \Rightarrow \frac{2}{\frac{1}{x-1}-1}=x \Rightarrow x^{2}-2=0, so x=2x=\sqrt{2} since x>0x>0.

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