Let be a regular octagon inscribed in a circle of unit radius. Diagonals meet at . Compute .
Solution
If is the center of the circle then is the incenter of . Moreover, PRIZ is a rhombus. It follows that is twice the inradius of a 1-1- triangle, hence the answer of . So . Alternatively, one can show (note, really) that the triangle is isosceles.
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