Let ABCD be a square of side length 5. A circle passing through A is tangent to segment CD at T and meets AB and AD again at X=A and Y=A, respectively. Given that XY=6, compute AT.
A number or a short expression. Spacing and $ signs are ignored.
Solution
Let O be the center of the circle, and let Z be the foot from O to AD. Since XY is a diameter, OT=ZD=3, so AZ=2. Then OZ=5 and AT=OZ2+25=30.
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