A perfect square is divisible by 9 exactly when its square root is divisible by 3. In other words, $n^{2}$ is divisible by 9 exactly when $n$ is divisible by 3. In the list $1,2,3, \ldots, 19,20$, there are 6 multiples of 3. Therefore, in the list $1^{2}, 2^{2}, 3^{2}, \ldots, 19^{2}, 20^{2}$, there are 6 multiples of 9.