Competition problem — Algebra — Maths Olympiad Prep

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Algebra Difficulty 1.9 Junior Find the answer

If $\sqrt{n+9}=25$ , what is the value of $n$ ?

Your answer

A number or a short expression. Spacing and $ signs are ignored.

Solution

Since $\sqrt{n+9}=25$ , then $n+9=25^{2}=625$ . Thus, $n=625-9=616$ .

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