A circle inscribed in a square has two chords as shown in a pair. It has radius 2, and bisects . The chords' intersection is where? Answer the question by giving the distance of the point of intersection from the center of the circle.
Solution
The point lies between and . Then is a parallelogram. For, by homothety at and because is an isoceles trapezoid. It follows that . Considering that the center of the circle together with points , and determines a square of side length 2, it follows that , so the answer is .
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