A circle inscribed in a square has two chords as shown in a pair. It has radius 2, and bisects . The chords' intersection is where? Answer the question by giving the distance of the point of intersection from the center of the circle.
HMMT February
Solution
The point lies between and . Then is a parallelogram. For, by homothety at and because is an isoceles trapezoid. It follows that . Considering that the center of the circle together with points , and determines a square of side length 2, it follows that , so the answer is .
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