Since $d$ is an odd integer, then $d+d$ is even and $d imes d$ is odd. Since $e$ is an even integer, then $e+e$ is even, which means that $(e+e) imes d$ is even. Also, $e+d$ is odd, which means that $d imes(e+d)$ is odd. Thus, 2 of the 4 expressions are equal to an odd integer.