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HMMT February

Algebra Difficulty 5.1 AIME, harder Find the answer

Define x⋆y=x2+3xy+y2−2x−2y+4xy+4x \star y=\frac{\sqrt{x^{2}+3 x y+y^{2}-2 x-2 y+4}}{x y+4}. Compute ((⋯((2007⋆2006)⋆2005)⋆⋯ )⋆1)((\cdots((2007 \star 2006) \star 2005) \star \cdots) \star 1)

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Note that x⋆2=x2+6x+4−2x−4+42x+4=(x+2)22(x+2)=12x \star 2=\frac{\sqrt{x^{2}+6 x+4-2 x-4+4}}{2 x+4}=\frac{\sqrt{(x+2)^{2}}}{2(x+2)}=\frac{1}{2} for x>−2x>-2. Because x⋆y>0x \star y>0 if x,y>0x, y>0, we need only compute 12⋆1=14+32+1−3+412+4=159\frac{1}{2} \star 1=\frac{\sqrt{\frac{1}{4}+\frac{3}{2}+1-3+4}}{\frac{1}{2}+4}=\frac{\sqrt{15}}{9}.

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