A point is equidistant from the coordinate axes if the vertical distance from the point to the -axis is equal to the horizontal distance from the point to the -axis. The point of intersection of the vertical line with the line with equation is equidistant from the coordinate axes. What is the sum of all possible values of ?
Solution
If , the distance from the vertical line with equation to the -axis is . If , the distance from the vertical line with equation to the -axis is . In each case, there are exactly two points on the vertical line with equation that are also a distance of or (as appropriate) from the -axis: and . These points lie on the horizontal lines with equations and , respectively. If the point lies on the line , then or . If the point lies on the line , then or . The sum of these values of is .
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