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CEMC Pascal

Algebra Difficulty 1.7 Junior Find the answer

If 3+△=53+\triangle=5 and △+□=7\triangle+\square=7, what is the value of △+Δ+Δ+□+□\triangle+\Delta+\Delta+\square+\square?

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Since 3+△=53+\triangle=5, then △=5−3=2\triangle=5-3=2. Since △+□=7\triangle+\square=7 and △=2\triangle=2, then □=5\square=5. Thus, △+Δ+Δ+□+□=3×2+2×5=6+10=16\triangle+\Delta+\Delta+\square+\square=3 \times 2+2 \times 5=6+10=16.

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