The function f satisfies f(x)+f(2x+y)+5xy=f(3x−y)+2x2+1 for all real numbers x,y. Determine the value of f(10).
A number or a short expression. Spacing and $ signs are ignored.
Solution
Setting x=10 and y=5 gives f(10)+f(25)+250=f(25)+200+1, from which we get f(10)=−49. Remark: By setting y=2x, we see that the function is f(x)=−21x2+1, and it can be checked that this function indeed satisfies the given equation.
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