Maths Olympiad Prep

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Algebra Difficulty 5.0 AIME Find the answer

The function ff satisfies f(x)+f(2x+y)+5xy=f(3xy)+2x2+1f(x)+f(2 x+y)+5 x y=f(3 x-y)+2 x^{2}+1 for all real numbers x,yx, y. Determine the value of f(10)f(10).

A number or a short expression. Spacing and $ signs are ignored.

Solution

Setting x=10x=10 and y=5y=5 gives f(10)+f(25)+250=f(25)+200+1f(10)+f(25)+250=f(25)+200+1, from which we get f(10)=49f(10)=-49. Remark: By setting y=x2y=\frac{x}{2}, we see that the function is f(x)=12x2+1f(x)=-\frac{1}{2} x^{2}+1, and it can be checked that this function indeed satisfies the given equation.

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