We are given triangle ABC, with AB=9,AC=10, and BC=12, and a point D on BC.B and C are reflected in AD to B′ and C′, respectively. Suppose that lines BC′ and B′C never meet (i.e., are parallel and distinct). Find BD.
A number or a short expression. Spacing and $ signs are ignored.
Solution
The lengths of AB and AC are irrelevant. Because the figure is symmetric about AD, lines BC′ and B′C meet if and only if they meet at a point on line AD. So, if they never meet, they must be parallel to AD. Because AD and BC′ are parallel, triangles ABD and ADC′ have the same area. Then ABD and ADC also have the same area. Hence, BD and CD must have the same length, so BD=21BC=6.
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