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Geometry Difficulty 5.0 AIME, harder Find the answer

A circle having radius r1r_{1} centered at point NN is tangent to a circle of radius r2r_{2} centered at MM. Let ll and jj be the two common external tangent lines to the two circles. A circle centered at PP with radius r2r_{2} is externally tangent to circle NN at the point at which ll coincides with circle NN, and line kk is externally tangent to PP and NN such that points M,NM, N, and PP all lie on the same side of kk. For what ratio r1/r2r_{1} / r_{2} are jj and kk parallel?

A number or a short expression. Spacing and $ signs are ignored.

Solution

Suppose the lines are parallel. Draw the other tangent line to NN and PP - since MM and PP have the same radius, it is tangent to all three circles. Let jj and kk meet circle NN at AA and BB, respectively. Then by symmetry we see that ANM=MNP=PNB=60\angle A N M=\angle M N P=\angle P N B=60^{\circ} since A,NA, N, and BB are collinear (perpendicular to jj and kk ). Let DD be the foot of the perpendicular from MM to ANA N. In MDN\triangle M D N, we have MN=2DNM N=2 D N, so r1+r2=2(r1r2)r_{1}+r_{2}=2\left(r_{1}-r_{2}\right), and so r1/r2=3r_{1} / r_{2}=3.

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