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CEMC Cayley

Algebra Difficulty 1.8 Junior Find the answer

If x=2yx = 2y and y≠0y \neq 0, what is the value of (x−y)(2x+y)(x-y)(2x+y)?

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Since x=2yx = 2y, then (x−y)(2x+y)=(2y−y)(2(2y)+y)=(y)(5y)=5y2(x-y)(2x+y) = (2y-y)(2(2y)+y) = (y)(5y) = 5y^{2}.

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