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CEMC Cayley

Geometry Difficulty 2.8 Junior Find the answer

What is the length of SRSR if in △PQR\triangle PQR, PSPS is perpendicular to QRQR, RTRT is perpendicular to PQPQ, PT=1PT=1, TQ=4TQ=4, and QS=3QS=3?

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Since PT=1PT=1 and TQ=4TQ=4, then PQ=PT+TQ=1+4=5PQ=PT+TQ=1+4=5. △PSQ\triangle PSQ is right-angled at SS and has hypotenuse PQPQ. By the Pythagorean Theorem, PS2=PQ2−QS2=52−32=16PS^{2}=PQ^{2}-QS^{2}=5^{2}-3^{2}=16. Since PS>0PS>0, then PS=4PS=4. Consider △PSQ\triangle PSQ and △RTQ\triangle RTQ. These triangles are similar, so PQQS=QRTQ\frac{PQ}{QS}=\frac{QR}{TQ}. Thus, 53=QR4\frac{5}{3}=\frac{QR}{4} and QR=203QR=\frac{20}{3}. Finally, SR=QR−QS=203−3=113SR=QR-QS=\frac{20}{3}-3=\frac{11}{3}.

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