The real numbers x,y,z,w satisfy 2x+y+z+w=1x+3y+z+w=2x+y+4z+w=3x+y+z+5w=25 Find the value of w.
A number or a short expression. Spacing and $ signs are ignored.
Solution
Multiplying the four equations by 12,6,4,3 respectively, we get 24x+12y+12z+12w6x+18y+6z+6w4x+4y+16z+4w3x+3y+3z+15w=12=12=12=75 Adding these yields 37x+37y+37z+37w=111, or x+y+z+w=3. Subtract this from the fourth given equation to obtain 4w=22, or w=11/2.
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