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Problem 192 Geometry Difficulty 1.3 Multiple choice CEMC Pascal · Canada · 2015
In the diagram, line segments P Q PQ P Q and R S RS R S intersect at T T T . The value of x x x is
Pick one
A 30 30 30
B 20 20 20
C 40 40 40
D 50 50 50
E 35 35 35
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Official solution Since the sum of the angles in a triangle is 180 ∘ 180^\circ 18 0 ∘ , then ∠ Q T R = 180 ∘ − ∠ T Q R − ∠ Q R T = 180 ∘ − 50 ∘ − 90 ∘ = 40 ∘ \angle QTR = 180^\circ - \angle TQR - \angle QRT = 180^\circ - 50^\circ - 90^\circ = 40^\circ ∠ QT R = 18 0 ∘ − ∠ T QR − ∠ QR T = 18 0 ∘ − 5 0 ∘ − 9 0 ∘ = 4 0 ∘ . Since opposite angles are equal, then ∠ S T P = ∠ Q T R = 40 ∘ \angle STP = \angle QTR = 40^\circ ∠ S T P = ∠ QT R = 4 0 ∘ . Since the sum of the angles in △ S T P \triangle STP △ S T P is 180 ∘ 180^\circ 18 0 ∘ , then ∠ P S T + ∠ S P T + ∠ S T P = 180 ∘ x ∘ + 110 ∘ + 40 ∘ = 180 ∘ x + 150 = 180 x = 30 \begin{aligned} \angle PST + \angle SPT + \angle STP & = & 180^\circ \\ x^\circ + 110^\circ + 40^\circ & = & 180^\circ \\ x + 150 & = & 180 \\ x & = & 30\end{aligned} ∠ P S T + ∠ S P T + ∠ S T P x ∘ + 11 0 ∘ + 4 0 ∘ x + 150 x = = = = 18 0 ∘ 18 0 ∘ 180 30 Therefore, the value of x x x is 30.
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Source: CEMC, University of Waterloo ,
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