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Problem 227

Geometry Difficulty 1.7 Multiple choice CEMC Gauss (Grade 7) · Canada · 2015

In a triangle, the measure of one of the angles is 4545^{\circ}. The measures of the other two angles in the triangle are in the ratio 4:54:5. What is the measure of the largest angle in the triangle?

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Official solution

Since the sum of the measures of the three angles in any triangle is 180°180\degree, then the sum of the measures of the two unknown angles in the given triangle is 180°45°=135°180\degree-45\degree=135\degree.

The measures of the two unknown angles are in the ratio 4:54:5, and so one of the two angle measures is 54+5=59\frac{5}{4+5}=\frac59 of the sum of the two angles, while the other angle measures 44+5=49\frac{4}{4+5}=\frac49 of the sum of the two angles.

That is, the larger of the two unknown angles measures 59×135°=75°\frac59\times135\degree=75\degree, and the smaller of the unknown angles measures 49×135°=60°\frac49\times135\degree=60\degree.

We may check that 60°+75°+45°=180°60\degree+75\degree+45\degree=180\degree.
The largest angle in the triangle measures 75°75\degree.

Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.