Before the hole was drilled, the volume of the block of wood was
$4 cm×4 cm×7 cm=112 cm}^3$.
The cylindrical hole has radius $1
cm} and height equal to that of the block of wood, 7 cm}$.
The volume of the cylindrical hole is thus $π×(1 cm)2×7 cm=7π cm}^3$.
In cm3, the volume of the
block of wood after the hole is drilled is 112−7π≈90.01, which when rounded
to the nearest cm3, is
90 cm3.