Maths Olympiad Prep

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Problem 631

AMC 10/12, early questions
Combinatorics Difficulty 3.8 Multiple choice CEMC Pascal · Canada · 2021

Azmi has four blocks, each in the shape of a rectangular prism and each with dimensions 2×3×62\times 3\times 6. She carefully stacks these four blocks on a flat table to form a tower that is four blocks high. The number of possible heights for this tower is

Pick one

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Official solution

The height of each block is 2, 3 or 6.

Thus, the total height of the tower of four blocks is the sum of the four heights, each of which equals 2, 3 or 6.

If 4 blocks have height 6, the total height equals 4×6=244 \times 6 = 24.

If 3 blocks have height 6, the fourth block has height 3 or 2.

Therefore, the possible heights are 3×6+3=213 \times 6 + 3 = 21 and 3×6+2=203 \times 6 + 2 = 20.

If 2 blocks have height 6, the third and fourth blocks have height 3 or 2.

Therefore, the possible heights are 2×6+3+3=182 \times 6 + 3 + 3 = 18 and 2×6+3+2=172 \times 6 + 3 + 2 = 17 and 2×6+2+2=162 \times 6 + 2 + 2 = 16.

If 1 block has height 6, the second, third and fourth blocks have height 3 or 2.

Therefore, the possible heights are 6+3+3+3=156 + 3 + 3 + 3= 15 and 6+3+3+2=146 + 3 + 3 + 2 = 14 and 6+3+2+2=136 + 3 + 2 + 2 = 13 and 6+2+2+2=126 + 2 + 2 + 2 = 12.

If no blocks have height 6, the possible heights are 3+3+3+3=123 + 3 + 3 + 3 = 12 and 3+3+3+2=113 + 3 + 3 + 2 = 11 and 3+3+2+2=103 + 3 + 2 + 2 = 10 and 3+2+2+2=93 + 2 + 2 + 2 = 9 and 2+2+2+2=82 + 2 + 2 + 2 = 8.

The possible heights are thus 24,21,20,18,17,16,15,14,13,12,11,10,9,824, 21, 20, 18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 8.

There are 14 possible heights.

Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.