Since the side lengths of the triangle are x−1, x+1 and 7, its perimeter is (x−1)+(x+1)+7 which equals 2x+7. Since x=10, the perimeter equals 2×10+7 which is equal to 27. Solution 2 Since x=10, the side lengths of the triangle are x−1=9 and x+1=11 and 7. The perimeter of the triangle is thus 9+11+7 which equals 27.