Maths Olympiad Prep

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Problem 833

AMC 12 late, AIME early
Geometry Difficulty 4.5 Prove it Annual Harvard-MIT November Tournament · United States

Let ABCABC be a triangle, and let MM be the midpoint of side ABAB. If ABAB is 1717 units long and CMCM is 88 units long, find the maximum possible value of the area of ABCABC.

This one wants a proof. Work it on paper, then read the official solution and mark yourself. Be honest about it: the record is only any use to you if it is.

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Official solution

Solution:

Answer: 6868

Let hh be the length of the altitude from CC to ABAB. Observe that K=12hAB12CMAB=68K = \frac{1}{2} \cdot h \cdot AB \leq \frac{1}{2} \cdot CM \cdot AB = 68 and that equality is achieved when CMABCM \perp AB.

Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.