Track / Stage 3 / 253 of 260 #253 of 2000

Problem:
What is the sum of all four-digit numbers that each use the digits $2, 4, 6$, and $8$ exactly once?

Your answer

Check

Show the answer

Official solution

Solution:
Every digit appears in each decimal place exactly $6$ times. Therefore, the sum is $6 \cdot (2+4+6+8) \cdot 1111 = 133,320$.

Source: MathNet, licensed CC-BY-4.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.