Maths Olympiad Prep

Track / Stage 6 / 120 of 400 #1120 of 1964

Problem 1120

National olympiad, first round
Algebra Difficulty 6.2 Prove it

[ Triangle Inequality (miscellaneous).]

a) Prove that when transitioning from a non-convex polygon to its convex hull, the perimeter decreases. (The convex hull of a polygon is the smallest convex polygon containing it.) b) Inside a convex polygon, there lies another convex polygon. Prove that the perimeter of the outer polygon is not less than the perimeter of the inner one.

This one wants a proof. Work it on paper, then read the official solution and mark yourself. Be honest about it: the record is only any use to you if it is.

Official solution

a) When transitioning from a non-convex polygon to its convex hull, some broken lines formed by the sides are replaced by straight-line segments (see figure). It remains to note that the length of the broken line is greater than the length of the segment with the same endpoints.

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b) Construct half-strips on the sides of the inner polygon, facing outward; the parallel edges of the half-strips are perpendicular to the corresponding side of the polygon (see figure). Let PP be the part of the perimeter of the outer polygon that lies within these half-strips. Then the perimeter of the inner polygon does not exceed PP, while the perimeter of the outer polygon is greater than PP.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.