1. **Assume the ordering of ωi**: Without loss of generality, let ω1>ω2>…>ωk. Define the sum S=ω1+ω2+…+ωk. Since the ωi are distinct and their sum is nonzero, S=0.
2. Identify the greatest and second greatest sums: Consider sums of the form 2ωπ(1)+ωπ(2)+…+ωπ(k) for permutations π of {1,2,…,k}. The greatest sum is 2ω1+ω2+…+ωk, and the second greatest sum is ω1+2ω2+ω3+…+ωk.
3. Use the density of rationals: Because the rationals are dense in the reals, we can find a rational number ϵ=ba with b>0 such that:
ω1+2ω2+…+ωk+Sϵ<0<2ω1+ω2+…+ωk+Sϵ
4. Formulate the inequalities: We can rewrite the inequalities as:
(2+ϵ)ω1+(1+ϵ)ω2+…+(1+ϵ)ωk>0
and
(1+ϵ)ω1+(2+ϵ)ω2+(1+ϵ)ω3+…+(1+ϵ)ωk<0
5. **Generalize for any permutation π**: For any non-identical permutation π of {1,2,…,k}, we have:
(2+ϵ)ωπ(1)+(1+ϵ)ωπ(2)+…+(1+ϵ)ωπ(k)<0
6. **Choose appropriate integers ni**: Let n1=b(2+ϵ)=2b+a and ni=b(1+ϵ)=b+a for 2≤i≤k. Then:
i=1∑kniωi=(2b+a)ω1+(b+a)ω2+…+(b+a)ωk
and for any non-identical permutation π:
i=1∑kniωπ(i)=(b+a)ωπ(1)+(2b+a)ωπ(2)+(b+a)ωπ(3)+…+(b+a)ωπ(k)
7. Verify the inequalities: By construction, the chosen ni satisfy:
i=1∑kniωi>0
and for any non-identical permutation π:
i=1∑kniωπ(i)<0
Thus, the integers n1,n2,…,nk exist and satisfy the required conditions.
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