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Stage 5 · Algebra

10 problems · AIME late · mathsolympiadprep.com

The answer key prints on its own page at the end.

  1. Let r1,r2,…,r7r_{1}, r_{2}, \ldots, r_{7} be the distinct complex roots of the polynomial P(x)=x7−7P(x)=x^{7}-7. Let K=∏1≤i<j≤7(ri+rj)K=\prod_{1 \leq i<j \leq 7}\left(r_{i}+r_{j}\right) that is, the product of all numbers of the form ri+rjr_{i}+r_{j}, where ii and jj are integers for which 1≤i<j≤71 \leq i<j \leq 7. Determine the value of K2K^{2}.

    HMMT November

    Algebra Solution and answer checking →

  2. The dimensions of a television screen are 60 cm×45 cm60~\mathrm{cm} \times 45~\mathrm{cm}. A camera films the entire television, and sends the image back onto the television itself, so that inside this television another one can be seen, and so on. The largest television seen inside the screen has an area equal to half the area of the screen. Assuming that a person watches the television seated at a distance such that they cannot distinguish images with an area smaller than 1 cm21~\mathrm{cm}^2, how many televisions does he see inside the screen?

    Progetto Olimpiadi di Matematica - GARA di SECONDO LIVELLO

    Algebra Solution and answer checking →

  3. Let g1(x)=13(1+x+x2+⋯ )g_{1}(x)=\frac{1}{3}\left(1+x+x^{2}+\cdots\right) for all values of xx for which the right hand side converges. Let gn(x)=g1(gn−1(x))g_{n}(x)=g_{1}\left(g_{n-1}(x)\right) for all integers n≥2n \geq 2. What is the largest integer rr such that gr(x)g_{r}(x) is defined for some real number xx ?

    HMMT November

    Algebra Solution and answer checking →

  4. MM is an 8×88 \times 8 matrix. For 1≤i≤81 \leq i \leq 8, all entries in row ii are at least ii, and all entries on column ii are at least ii. What is the minimum possible sum of the entries of MM ?

    HMMT February

    Algebra Solution and answer checking →

  5. Simplify the expression: (cos⁡2π3+isin⁡2π3)6+(cos⁡4π3+isin⁡4π3)6\left(\cos \frac{2 \pi}{3}+i \sin \frac{2 \pi}{3}\right)^{6} + \left(\cos \frac{4 \pi}{3}+i \sin \frac{4 \pi}{3}\right)^{6} using DeMoivre's Theorem.

    HMMT February

    Algebra Solution and answer checking →

  6. Let S0=0S_{0}=0 and let SkS_{k} equal a1+2a2+…+kaka_{1}+2 a_{2}+\ldots+k a_{k} for k≥1k \geq 1. Define aia_{i} to be 1 if Si−1<iS_{i-1}<i and -1 if Si−1≥iS_{i-1} \geq i. What is the largest k≤2010k \leq 2010 such that Sk=0S_{k}=0?

    HMMT February

    Algebra Solution and answer checking →

  7. Define a sequence ai,ja_{i, j} of integers such that a1,n=nna_{1, n}=n^{n} for n≥1n \geq 1 and ai,j=ai−1,j+ai−1,j+1a_{i, j}=a_{i-1, j}+a_{i-1, j+1} for all i,j≥1i, j \geq 1. Find the last (decimal) digit of a128,1a_{128,1}.

    HMMT February

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  8. Compute the number of quadruples (a,b,c,d)(a, b, c, d) of positive integers satisfying 12a+21b+28c+84d=202412a+21b+28c+84d=2024.

    HMMT February

    Algebra Solution and answer checking →

  9. Let P(x)=x4+2x3−13x2−14x+24P(x)=x^{4}+2 x^{3}-13 x^{2}-14 x+24 be a polynomial with roots r1,r2,r3,r4r_{1}, r_{2}, r_{3}, r_{4}. Let QQ be the quartic polynomial with roots r12,r22,r32,r42r_{1}^{2}, r_{2}^{2}, r_{3}^{2}, r_{4}^{2}, such that the coefficient of the x4x^{4} term of QQ is 1. Simplify the quotient Q(x2)/P(x)Q\left(x^{2}\right) / P(x), leaving your answer in terms of xx. (You may assume that xx is not equal to any of r1,r2,r3,r4)\left.r_{1}, r_{2}, r_{3}, r_{4}\right).

    HMMT November

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  10. A sequence {an}n≥0\left\{a_{n}\right\}_{n \geq 0} of real numbers satisfies the recursion an+1=an3−3an2+3a_{n+1}=a_{n}^{3}-3 a_{n}^{2}+3 for all positive integers nn. For how many values of a0a_{0} does a2007=a0a_{2007}=a_{0} ?

    HMMT February

    Algebra Solution and answer checking →

Answer key — Stage 5 · Algebra

Worked solutions for every problem are on the site, one page per problem.

  1. 117649117649 open
  2. 1111 open
  3. 55 open
  4. 372372 open
  5. 22 open
  6. 10921092 open
  7. 44 open
  8. 20242024 open
  9. x4−2x3−13x2+14x+24x^{4}-2 x^{3}-13 x^{2}+14 x+24 open
  10. 320073^{2007} open

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