Maths Olympiad Prep

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Stage 6 · Geometry

10 problems · National Olympiad, first round · mathsolympiadprep.com

The answer key prints on its own page at the end.

  1. Given the triangle ABCABC right-angled at AA, we construct on the hypotenuse the square BCDEBCDE (with D,ED, E on the opposite side of AA with respect to BCBC). Knowing that the areas of triangles ABEABE and ACDACD are respectively 6 m26~\mathrm{m}^2 and 27 m227~\mathrm{m}^2, what is the area of triangle ABCABC?

    1. A32 m23 \sqrt{2}~m^2
    2. B6 m26~\mathrm{m}^2
    3. C12 m212~\mathrm{m}^2
    4. D92 m29 \sqrt{2}~\mathrm{m}^2
    5. E18 m218~\mathrm{m}^2

    Progetto Olimpiadi della Matematica

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  2. A rectangle with side lengths 11 and 33, a square with side length 11, and a rectangle RR are inscribed inside a larger square as shown. The sum of all possible values for the area of RR can be written in the form mn\frac{m}{n}, where mm and nn are relatively prime positive integers. What is m+nm + n?
    Figure 1

    1. A14
    2. B23
    3. C46
    4. D59
    5. E67

    Fall AMC 10 B 2021

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  3. In the cyclic quadrilateral ABCDABCD, the diagonal ACAC bisects the angle DABDAB. The side ADAD is extended beyond DD to a point EE. Show that CE=CACE = CA if and only if DE=ABDE = AB.

    BMO Round 1 2006

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  4. Let ABCABC be an acute-angled triangle. The feet of the altitudes from AA, BB and CC are DD, EE and FF respectively. Prove that DE+DF≤BCDE + DF \leq BC and determine the triangles for which equality holds.

    The altitude from AA is the line through AA which is perpendicular to BCBC. The foot of this altitude is the point DD where it meets BCBC. The other altitudes are similarly defined.

    BMO Round 1 2012

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  5. For a given quadrilateral A1A2B1B2A_1A_2B_1B_2 point PP is called phenomenal, if line segments A1A2A_1A_2 and B1B2B_1B_2 subtend the same angle at point PP (i.e. triangles PA1A2PA_1A_2 and PB1B2PB_1B_2 which can be also also degenerate have equal inner angles at point PP disregarding orientation).

    KöMaL problem A 2021

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  6. In the acute angled triangle ABCABC, the midpoints of the sides BCBC, CACA and ABAB are DD, EE and FF, respectively. The foot of the altitude of the triangle starting from CC is T1T_1. On some line, passing through point CC but not containing T1T_1, the feet of the perpendiculars starting from AA and BB are T2T_2 and T3T_3, respectively. Prove that the circle DEFDEF passes through the center of the circle T1T2T3T_1T_2T_3.
    Proposed by: Bálint Bíró, Eger
    (5 pont)

    KöMaL problem A 2015

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  7. The excircle to the side ABAB of a triangle ABCABC is tangent to the circle with diameter BCBC. Find ACB\text{ACB} if the lengths of the sides BCBC, CACA and ABAB form (in this order) an arithmetic progression.

    Bulgarian Mathematical Competitions

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  8. Assume that positive numbers aa, bb, cc, xx, yy, zz satisfy cy+bz=acy + bz = a; az+cx=baz + cx = b and bx+ay=cbx + ay = c. Find the minimum value of the function f(x,y,z)=x21+x+y21+y+z21+zf(x, y, z) = \frac{x^2}{1+x} + \frac{y^2}{1+y} + \frac{z^2}{1+z}.

    China Mathematical Competition (Extra Test)

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  9. Given a cyclic hexagon ABCDEFABCDEF, let BDBD and CFCF meet at GG, ACAC and BEBE meet at HH, ADAD and CECE meet at II. Suppose that BDBD is perpendicular to CFCF and AI=CIAI = CI. Show that CH=AH+DECH = AH + DE if and only if GH⋅BD=BC⋅DEGH \cdot BD = BC \cdot DE.

    Korean Mathematical Olympiad Final Round

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  10. Let ABCDABCD be a cyclic quadrilateral. The lines ADAD, BCBC meet at PP; ABAB, CDCD at QQ; and ACAC, BDBD at RR. The perpendicular bisectors of ABAB, respectively BCBC, meet PRPR at XX, respectively QRQR at YY. Prove that XYXY passes through BB.

    Local Mathematical Competitions

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Answer key — Stage 6 · Geometry

Worked solutions for every problem are on the site, one page per problem.

  1. DD open
  2. EE open
  3. Prove it — see the worked solution open
  4. Prove it — see the worked solution open
  5. Prove it — see the worked solution open
  6. Prove it — see the worked solution open
  7. Prove it — see the worked solution open
  8. Prove it — see the worked solution open
  9. Prove it — see the worked solution open
  10. Prove it — see the worked solution open

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